Per resoldre aquest problema s'han d'utlitzar les següents equacions i passos:
\begin{align} &\cssId{Step1}{E_{1}=E_{cicle1}·{3·3600 \over t_{cicle1}}}\\[3px] &\cssId{Step2}{E_{1}=((P_{P}+P_{A}+P_{U})·2)·{3·3600 \over 2·3}}\\[3px] &\cssId{Step3}{E_{1}=((92,90+99,96+95,30)·2)·{10800 \over 6}=1,037·10^6 J}\\[3px] &\cssId{Step4}{E_{1}=1,037·10^6·{0,0002778 Wh \over 1 J}=0,2882 kWh}\\[3px] &\cssId{Step5}{E_{2}=E_{cicle2}·{3·3600 \over t_{cicle2}}}\\[3px] &\cssId{Step6}{E_{2}=((P_{P}+2·P_{A}+P_{U})·2)·{3·3600 \over 2·4}}\\[3px] &\cssId{Step7}{E_{2}=((92,90+2·99,96+95,30)·2)·{10800 \over 8}=1,048·10^6 J}\\[3px] &\cssId{Step8}{E_{2}=1,048·10^6·{0,0002778 Wh \over 1 J}=0,2911 kWh}\\[3px] \end{align}